(40x^2-13x+1)=0

Solution for (40x^2-13x+1)=0 equation:

Simplifying
(40x2 + -13x + 1) = 0

Reorder the terms:
(1 + -13x + 40x2) = 0

Remove parenthesis around (1 + -13x + 40x2)
1 + -13x + 40x2 = 0

Solving
1 + -13x + 40x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(1 + -8x)(1 + -5x) = 0

Subproblem 1
Set the factor '(1 + -8x)' equal to zero and attempt to solve:

Simplifying
1 + -8x = 0

Solving
1 + -8x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -8x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -8x = 0 + -1
-8x = 0 + -1

Combine like terms: 0 + -1 = -1
-8x = -1

Divide each side by '-8'.
x = 0.125

Simplifying
x = 0.125
Subproblem 2
Set the factor '(1 + -5x)' equal to zero and attempt to solve:

Simplifying
1 + -5x = 0

Solving
1 + -5x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -5x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -5x = 0 + -1
-5x = 0 + -1

Combine like terms: 0 + -1 = -1
-5x = -1

Divide each side by '-5'.
x = 0.2

Simplifying
x = 0.2
Solution
x = {0.125, 0.2}